At a bus station, buses begin their routes at 6 a. m. the schedule for two of the buses is based on the time intervals listed below. ~bus a leaves every 75 minutes ~bus b leaves every 15 minutes what is the next time bus a and bus b will leave the bus station at the same time? pls explain! : d

The next time both will leave the bus station at the same time is 7:15 a.m.

Step-by-step explanation:

Since 15 and 75 are multiples to each other.

So, L.C.M. of 15 and 75 is 75.

So, after 75 minutes both buses will leave the station at the same time.

Also since buses begin their routes at 6 a.m.

So, next time they will meet at

6 hours 0 minutes + 75 minutes = 7 hours 15 minutes = 7:15 a.m.

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form

dont think so

step-by-step explanation: