Hector drew nop with the coordinates (4,2) (5,3) , and (6,2) then he drew an image of this triangle with coordinates (-4,2) -5,3) and (-6,2) what is the line of reflection for this image

The line of reflection for this image is the y-axis

Step-by-step explanation:

we know that

The rule of a reflection of a point across the y-axis is equal to

(x,y) > (-x,y)

In this problem we have

the coordinates (4,2),(5,3) and (6,2)

Applying reflection across the y-axis

(4,2) > (-4,2)

(5,3) > (-5,3)

(6,2) > (-6,2)

therefore

The line of reflection for this image is the y-axis

2.2°  

step-by-step explanation:

let θ = the angle of elevation.

tanθ =77/2020

tanθ = 0.038 12

      θ = tan⁻¹0.038 12

      θ = 2.2°