The probability of buying a movie ticket with a popcorn coupon is 0.608. if you buy 10 movie tickets, what is the probability that 3 or more of the tickets have popcorn coupons? (round your answer to 3 decimal places if necessary.)

0.989

Step-by-step explanation:

The probability of buying a movie ticket with a popcorn coupon is p = 0.608, so the probability of buying a movie ticket without a popcorn coupon is q = 1 - 0.608 = 0.392.

Find the following probabilities;

Hence, the probability that 3 or more of the tickets have popcorn coupons is

P(3 or more of the tickets have popcorn coupons) = 0.989

Step-by-step explanation:

The probability of buying a movie ticket with a popcorn coupon is 0.608

p = 0.608

The probability of buying a movie ticket without a popcorn coupon is q

q = 1 - p = 1 - 0.608 = 0.392

If you buy 10 movie tickets, n = 10

The probability that 3 or more of the tickets have popcorn coupons.

X = 3,4,5,6,7,8,9,10

Using Binomial distribution,

p = Success , q = failure, n = number of trial , r = X

For X = 3,4,5,6,7,8,9,10

Let E be probability 3 or more of the tickets have popcorn coupons.

Now round to 3 decimal place.

P(3 or more of the tickets have popcorn coupons) = 0.989

after simplifying it i got: -36.25 as my answer. hope that !

the answer is b