Let n > 5. a deck containing 4n cards has exactly n cards each of four diffrent suits numbered from the set [n]. using the method of choice (or otherwise) in how many ways can five cards be chosen so that they contain: (a) five consecutive cards of the same suit? (ie. the set of numbers on the cards is li, i +41) (b) four of the five cards have the same number? (c) exactly three of the cards have the same number? (d) not more than two cards of the same suit? hint: consider two cases.

the final amount you will pay is $68.04.

the tip is determined by the pre-tax amount, so we calculate the tip based on the original bill, not after we've added sales tax.

to find the tip:

we can divide 54.00 by 100 to get 1% of 54. then we multiply that by 18.

54 / 100 = .54

.54 x 18 = 9.72

tip = 9.72$

to find the tax:

we can divide 54.00 by 100 to get 1% of 54. then we can multiply that by 8 to get 8%.

54 / 100 = .54

.54 x 8 = 4.32

tax= 4.32

now we can add the tip and tax to the bill to get our total.

54 + 9.72 + 4.32 = 68.04

total: $68.04

step-by-step explanation: