13. physics students use a spring scale to measure the weight of a piece of lead. the experiment was performed two times: once in the air and once in water. if the volume of lead is 50 cm3, what is the difference between the two readings on the scale?

In the air the scale will measure 5.56 N for the weight of the piece of lead.

In the water the piece of lead will have a weight of 0.65 N.

Step-by-step explanation:

We have to use the Archimedes' principle, that is, the upward force felt by a submerge object in a fluid is equal to the wight of the displaced volume of the object. In other words where is the density of the fluid in , V is the volume of the submerged object in and g is the gravitational constant with a value of .

The lead has a volume density of , the volume of the lead is .

The mass of the lead is given by

Thus its weight in the air is .

On the other hand when submerged the piece of lead will feel an upward force :

.

The perceived weight by the submerged piece of lead will be:

the correct answer is 1: 2

step-by-step explanation:

hope this your welcome : )

answer:   y=2x-3

step-by-step explanation: