17 how many integer solutions are there to the equation x 1 + x 2 + x 3 + x 4 = 132 x1+x2+x3+x4=132 provided that x 1 > 0 , x1> 0, and x 2 , x 3 , x 4 ≥ 0 ? x2,x3,x4≥0? what if we add the restriction that x 4 < 17 ?

2 x t divided by n

step-by-step explanation:

step-by-step explanation:

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2