Rewrite the expression in the form z^nz n z, start superscript, n, end superscript. z^{-11}\cdot z^{-15}=z −11 ⋅z −15 =z, start superscript, minus, 11, end superscript, dot, z, start superscript, minus, 15, end superscript, equals

1. use commutative property to reorder the terms.2x+81=0.2. move the constant to right side by adding its opposite on both sides. 2x+81-81=0-81.2x=(-81).3. divide the equation on both sides.2x ÷ 2 = 81 ÷ 2.x = -81/2. your answer is -81/2. if you need to simplify it into a decimal, it’s -40.5.