Acertain cd-rom disk can store approximately 6.0 × 102 megabytes of information, where 106 bytes = 1 megabyte. if an average word requires 14 bytes of storage, how many words can be stored on one disk?
a. 4.3 × 107 words
b. 2.1 × 107 words
c. 8.4 × 109 words
d. 2.0 × 109 words

A.

Step-by-step explanation:

Given : A certain CD-ROM disk can store approximately  megabytes of information.

1 megabyte = bytes

Then, The storage capacity of CD-ROM disk will be :

If an average word requires 14 bytes of storage, then the number of words can be stored :-

Hence,  number of words can be stored =

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.