Atriangle has vertices a(1,1), b(2,4), and c(4,2). line p is parallel to side ab and contains point c. write an equation for line p.
part 1. find the slope of ab
use the slope of part 1and point c to write an equation for line p in slope-intercept form.

2. Given the points A, B, C, D, calculate:

(a) the angle B of the triangle ABC

(b) the area of the triangle ABC

(c) the median BE of the triangle ABC

(d) the height AH of the triangle ABC

(e) the volume of tetrahedron ABCD

(f) the point E so that ABCE is a parallelogram.

A(-1, 2, -3), B(4, -1, 0), C(2, 1, -2), D( 3,4,5)

Step-by-step explanation:

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step-by-step explanation:

it works trust me

starting with:    

5 + x - 12 = 2x - 7   

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)   

5 - 12 = x - 7 (combine and cancel x's from both sides)   

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)   

0 = x (add numbers together on both sides)       

so in order for the equation to be true, x must be 0.   

trying x = -0.5   

5 + x - 12 = 2x - 7 (original equation)   

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)   

5 + -0.5 - 12 = -1 - 7 (did multiplication)   

-7.5 = -8 (did addition on both sides)       

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.   

trying x = 0   

5 + x - 12 = 2x - 7 (original equation)   

5 + 0 - 12 = 2(0) - 7 (plug in value of x)   

5 + 0 - 12 = 0 - 7 (did multiplication)   

-7 = -7 (did addition on both sides)       

since -7 equals -7, that demonstrates that the value of 0 for x is correct.   

trying x = 1   

5 + x - 12 = 2x - 7 (original equation)   

5 + 1 - 12 = 2(1) - 7 (plug in value of x)   

5 + 1 - 12 = 2 - 7 (did multiplication)   

-6 = -5 (did addition on both sides)       

since -6 is obviously not equal to -5, the value of 1 for x is wrong.