Lines a and b are cut by transversal f. at the intersection of lines f and a, the top left angle is 96 degrees. at the intersection of lines b and f, the bottom right angle is (6 x minus 36) degrees.
what must be the value of x so that lines a and b are parallel lines cut by transversal f?
10
20
22
32

C. 22

Step-by-step explanation:

Inverse Alternate Interior Angles Theorem sttes that if two lines a and b are cut by transversal f so that the alternate interior angles are congruent, then a║b.

To prove that lines a and b are parallel, equate the measures of angles 96° and (6x-36)°:

Option C.

Step-by-step explanation:

It is given that lines a and b are cut by transversal f.

If a transversal line intersect two parallel lines, then the alternate exterior angles are same.

We need to find the value of x so that lines a and b are parallel lines cut by transversal f.

So, equate both alternate exterior angles.

Add 36 on both sides.

Divide both sides by 6.

The value of x is 22. Therefore, the correct option is C.

rectangle: 9 1/8 x 4 1/9 = 37 37/72in

parallelogram: b times h= 10.3 x 6.2 = 63.86

trapezoid: a+b/2 times h= 42.5

volume of prism: l times w times h= 36

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.