Find the laplace transform y(s) of the solution of the given initial value problem. then invert to find y(t) . write uc for the heaviside function that turns on at c , not uc(t) . y'' + 9y = 1, 0 ≤ t < 2, 0, 2 ≤ t < [infinity]; y(0) = 3, y'(0) = 2

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

it is a secret for it not to be compromised sorry

step-by-step explanation:

the weight of the object inside the box!