Atriangle with angles measuring 45°, 50°, and 85° has sides with lengths of 16.34 cm, 12.57 cm, and 11.60 cm. what is the length of the side opposite the 85° angle?

16.34m

Step-by-step explanation:

Since 85 is the widest angle, it follow that the opposing segment must be the longest.

Assuming this we can verify with the cosine theorem:

c² = a² + b² − 2ab cos(C)

16.34² = 12.57² + 11.60² - 2*11.60*12.57.cos(85°) ?

266.99 = 158.00 + 134.56 - 291.62 * 0.087

266.99 = 266.99

Solving both sides independently, we arrive to the same number, proving our hypothesis

proofs involving isosceles triangles often require special consideration because an isosceles triangle has several distinct properties that do not apply to normal triangles.(more about triangle types) therefore, when you are trying to prove that two triangles are congruent, and one or both triangles, are isosceles you have a few theorems that you can use to make your life easier.

step-by-step explanation:

an isosceles triangle has two congruent sides and two congruent angles. the congruent angles are called the base angles and the other angle is known as the vertex angle. ∠bac and ∠bca are the base angles of the triangle picture on the left. the vertex angle is ∠abc

t

step-by-step explanation:

ever thing time 1 is a multiply by 1 it get