Person a leaves his home to visit his cousin, person b who lives 76 miles away. he travels at an average rate of 44 miles per hour. one half hour later person b leaves her house to visit person a traveling at an average rate
of 64 miles per hour. how long after person b leaves will it be before they meet?

There are going to meet half a hour after person B leaves.

Step-by-step explanation:

The first step to solve this problem is model the position equation for both person A and person B. It can be done by a first order equation.

I am going to say that the positive direction is from the person A to the person B. So, A starts at the position 0 and B at the position 76.

The first step is to find the equation of the position of person A

The initial position of A is 0 and he travels 44 miles per hour in the direction of B, so to the positive diretion. So, the position S of person A is

,

where t is the time in hours.

Now we have to find the equation of the position of person B

The initial position of B is 76 and he travels 64 miles per hour in the direction A, so in the negative direction. The position S of person B is

Now we have to restart the time from the moment the person B leaves her house.

It happens at 0.5h, at this moment the person A is at the position

So, from this moment, the equation of the position of A is:

They will meet at the instant t when

t = 0.5h

There are going to meet half a hour after person B leaves.

the data of the detroit pistons in numerical order from least to greatest is 0.30, 0.37, 0.55, 0.62, 0.69, 0.72, 0.73, 0.75, 0.77, 0.78, 0.80, 0.81, 0.81, 0.83, 0.84, 0.89

the data of the miami heat in numerical order from least to greatest is 0.50, 0.50, 0.56, 0.57, 0.67, 0.72, 0.72, 0.72, 0.75, 0.75, 0.76, 0.81, 0.82, 0.90, 1.00, 1.00

the detroit pistons median : 1.52

the miami heat median: 1.47

the iqr of this data is 0.05