Let a = {the rationals) and b = {the irrationals). find au b.
a) the integers
b) the reals
c) the rationals
d) the irrationals
its not c, or d

Option B.

Step-by-step explanation:

It is given that

A = {The Rationals}

B = {The Irrationals}

We need to find the set A∪B.

If we have two sets X and Y then union of these sets (X∪Y) contains all the elements of set X, of set Y or both.

It is given that A is the set of rations and B is the set of irrational, so the union A∪B is the combined set of all rational or irrational numbers.

A∪B = {The Rationals} +  {The Irrationals}

A∪B = {The Reals}

Therefore, the correct option is B.

2(2x + 3) = -4 + 2(2x + 5)

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 6

4x - 6 + 6 = 4x - 6 + 6

4x = 4x

x = x

unlimited solutions.