You are given that the following set of statements are true. (a) if an integer is even, then it is cosmological. (b) if a real number is cosmological, then it is not mystical. (c) if two real numbers are not mystical, then their product is mystical. provide a proof by contradiction for the following statement: it is true that at least one of v2 or 18 is mystical.

18 is even, so by rule (a) cosmological, let's call it C. 18 is real and C and so by (b) not mystical, not M.  

So V2 which I guess is is our only hope.

Assume is not M.

Then is M, as by (c) it's the product of two not M numbers.

2 is even, so 2 is C (rule (a)).  So 2 is not M (rule (b)).  That's a contradiction.

Therefore our assumption is false.  We conclude

is mystical.

50.6

step-by-step explanation:

exa:

)

3+11

14

step-by-step explanation:

from this example, we can see that subtracting with integers is the same as adding the opposite. we can solve using a number line or by using the saying "keep, change, change" to us solve. it is important to remember that we can subtract a negative and end up with a larger number than we started with.