Asurvey found that women's heights are normally distributed with mean 63.2 in. and standard deviation 2.4 in. the survey also found that men's heights are normally distributed with a mean 67.2 in. and standard deviation 2.7. complete parts a through c below. a. most of the live characters at an amusement park have height requirements with a minimum of 4 ft 9 in. and a maximum of 6 ft 2 in. find the percentage of women meeting the height requirement?

99.51%

Step-by-step explanation:

Given : A survey found that women's heights are normally distributed.

Population mean :

Standard deviation:

Minimum height = 4ft. 9 in.=

Maximum height = 6ft. 2 in.=

Let x be the random variable that represent the women's height.

z-score :

For x=57, we have

For x=74, we have

Now, by using the standard normal distribution table, we have

The probability of women meeting the height requirement :-

Hence, the percentage of women meeting the height requirement = 99.51%

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.