Arectangle has a height of c^3+6c^2+2c and a width of c^2+1.
express the area of the entire rectangle.

  area = c^5 + 6c^4 +3c^3 +6c^2 +2c

Step-by-step explanation:

Area is the product of height and width:

  area = (c^3 +6c^2 +2c)(c^2 +1)

  = (c^5 +6c^4 +2c^3) +(c^3 +6c^2 +2c)

  = c^5 + 6c^4 +3c^3 +6c^2 +2c

answer: (x)+4-5=-3

step-by-step explanation:

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option