Find the sum of the arithmetic series in which a1 = –68, d = –3, and n = 20.

Sum = -1930

Step-by-step explanation:

Sum of an arithmetic series;

;Sum = n/2[ 2a1 + ( n - 1 )d]

Then substitute into the equation above

; Sum = 20/2 [ 2(-68) + (19)-3 ]

; Sum = 10 [ -136 - 57 ]

Therefore the sum of the arithmetic series

is; -1930

the answer is 9.8975

explanation:

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step-by-step explanation:

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph