A, b, and c are collinear, and b is between a and c. the ratio of ab is 1: 1. if a is at (1,-9) and b is at (2,0), what are the coordinates of point c

(3,9)

Step-by-step explanation:

So I drew a right triangle with the line segment A(1,-9) to C as the hypotenuse.  This line segment does contain point B(2,0). This is shown in the picture.

We want to find a point C so that AB to BC has a ratio of 1:1. So this means B is the midpoint really.

So if we averaged the endpoints of the line segment it would equate to point B.

That is:

and

Multiply both sides by 2:

and

The first equation can be solved by subtracting 1 on both sides giving .

The second equation can be solved by adding 9 on both sides giving

.

Point C is (3,9).

answer: f = 32.2m

step-by-step explanation: that is the answer

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0