A2x2 matrix m is given by (ab) lcd) given that a = 19, b = 24 and c = 38, what is the value of d such that the matrix mis singular. give your answer to the nearest integer.

Value of d is:

48

Step-by-step explanation:

We are given a matrix M as:

M=

We are given that:

a=19, b=24 and c=38

We have to find the value of d so that M is singular

i.e. determinant of M=0

i.e. ad-bc=0

i.e. 19d-24×38=0

i.e. 19d=24×38

i.e. d=

i.e. d=48

Hence, Value of d is:

48

m∠5 + m∠3 = m∠1   is true.

m∠5 + m∠6 = 180 is true

m∠2 +m∠3 = m∠6   is true

m∠2 +m∠3 +m∠5 = 180   is true