Aball is thrown vertically in the air with a velocity of 95 ft/s. what time in seconds is the ball at a height of 120ft. round to the nearest tenth of a second .

On the way up, 1.8 seconds and on the way down 4.1 seconds.

Step-by-step explanation:

Use the  motion under gravity  equation s = ut + 0.5gt^2 where u = initial velocity, s = the height, t = time and g = acceleration due to gravity ( 32 fts-2).

So 120 = 95t + 0.5(-32)t^2

-16t^2 + 95t - 120 = 0

Solving this using the quadratic formula:

t = [-95 +/- √(95^2 - 4 * -16*-120)] / -32

t = 1.823, 4.1148.

The first value refers to the upward journey and the second to the downward journey.

ii6tyhj7 juj3yyj333ju jmyhthhtk7h jg hajj jiijh

she was supposed to add the hours(38.5) and multiply the amount of money she earned(7.50) resulting in $288.75 .

correct me if i'm wrong and if it is i'm truly sorry.