Mathematics, 29.08.2019 03:30 queenkimm26

In a study, 37 % of adults questioned reported that their health was excellent. a researcher wishes to study the health of people living close to a nuclear power plant. among 13 adults randomly selected from this area, only 3 reported that their health was excellent. find the probability that when 13 adults are randomly selected, 3 or fewer are in excellent health. round to three decimal places.

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Answer from: davidchafin59245

0.230

Step-by-step explanation:

Probability of an adult being in excellent health = p = 37% = 0.37

There are only 2 outcomes of the event i.e. in excellent health or not.Number of trials is fixed i.e. n = 13Probability of success is constantEvents are independent i.e. answer of individuals is not influenced by answers of others

This satisfies all the 4 conditions that are needed for a Binomial Experiment. Hence, we can solve the given question using Binomial Probability.

p = 0.37

q = 1 - p = 1 - 0.37 = 0.63

n = 13

We need to find the probability that when 13 adults are randomly selected, 3 or fewer are in excellent health i.e. P( x ≤ 3 )

P( x ≤ 3 ) = P(0) + P(1) + P(2) + P(3)

The formula of Binomial probability is:

$P(x)=^{n}C_{x}(p)^{x}(q)^{(n-x)}$

So,

$P(0)=^{13}C_{0}(0.37)^{0}(0.63)^{(13-0)}=0.0025\\\\ P(1)=^{13}C_{1}(0.37)^{1}(0.63)^{(13-1)}=0.0188\\\\ P(2)=^{13}C_{2}(0.37)^{2}(0.63)^{(13-2)}=0.0663\\\\ P(3)=^{13}C_{3}(0.37)^{3}(0.63)^{(13-3)}=0.1427$

Thus,

P( x ≤ 3 ) = P(0) + P(1) + P(2) + P(3) = 0.0025 + 0.0188 + 0.0663 + 0.1427

P( x ≤ 3 ) = 0.2303

Therefore, the probability that when 13 adults are randomly selected, 3 or fewer are in excellent health is 0.230

Answer from: Quest

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf =

pf = 6,25 u

ver más en -

step-by-step explanation:

Answer from: Quest

1+1=22×1=22-1=11-1=1duh

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