Sketch the polar curves r = 6 sin θ and r = 2+ 2 sin θ, then set up an integral that represents the area inside r = 6 sin θ and outside r = 2 + 2 sin θ. do not evaluate your integral.

Step-by-step explanation:

Given are two polar curves as

Let us find the point/s of intersection

Eliminate r to get

Thus we find that area outside II curve and inside first curve would be

where lower limit is 30 degrees and 150 degrees.

it is only things thain can be deafeated

step-by-step explanation:

answer: 5

step-by-step explanation:

since, the range is the difference between the lowest and highest values of the given sample space.

and, here the sample space = { 3, 1, 0, 4, 1, 4, 2, 3, 0, 5, 0, 1, 1, 2, 0, 4, 1,4, 4 ,2 ,3 ,2 ,0 ,1 ,4 }

here, the highest value of the given sample = 5

and, the lowest value = 0

therefore, the range of the sample space = 5 - 0 = 5