What is the minimum sample size needed to estimate a population proportion to within 5% with 98% confidence? assume that there is no prior knowledge of the true value of the proportion, and enter your answer as a whole number.

543

Step-by-step explanation:

When we have no prior knowledge of the true value of the proportion, then the formula to find the minimum sample size is given by :-

Given : Margin of error : E = 0.05

Significance level :

By standard normal distribution table , the critical value will be :-

Then,

Hence, the  minimum sample size needed to estimate a population proportion = 543

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

the two may have that, even a breakdown is probably offered