Mathematics, 27.08.2019 19:10 jmchmom6066
Consider a cylindrical object such that its diameter is always half its height. if the cylinder is shrinking in a such a way that its height is reducing at a rate of 2 cm/minute and its initial height (at time t=0) is 40 cm, find a formula for the volume of the cylinder in terms of time t measured in minutes. you may use the volume formula for a cylinder v=ฯr2h.
Answers: 3
is a function of time, we have to 
. Integrating 
and applying the first fundamental theorem of the calculation you get:
. Since 
, you have to 
and therefore, 
and 
or what is equal 
. With all this,
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