Probabilities with possible states of nature: s1, s2, and s3. suppose that you are given a decision situation with three possible state of nature: s1, s2, and s3.the prior probabilities are p(s1) =.1, p(s2) = .6, and p(s3) = .3.with sample information i, p(i|s1) =.15, p(i|s2) = .2, and p(i|s3) = .1.compute p(s1|i)compute p(s2|i)compute p(s3|i)

1.

2.

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Step-by-step explanation:

Given information:

(1)

We need to find the value of P(s₁|I).

Therefore the value of P(s₁|I) is .

(2)

We need to find the value of P(s₂|I).

Therefore the value of P(s₂|I) is .

(3)

We need to find the value of P(s₃|I).

Therefore the value of P(s₃|I) is .

the correct answer option is (2x-3)(2x+3).

step-by-step explanation:

we are given the following expression and we are to factorize it:

we are to find such factors that when multiplied they give a result of 36 (9 x 4 = 36) and when added they give a result of 0.

the two such factors of 36 are negative six and postive six.

factorizing the given expression to get:

therefore, the correct factorization of is (2x-3)(2x+3).