The distribution of the amount of a certain brand of soda in 16 oz bottles is approximately normal with a mean of 16.12 oz and a standard deviation of 0.09 oz. the percentage of the soda bottles that contain more than the 16 oz advertised is: %

90.82%

Step-by-step explanation:

Given : The distribution of the amount of a certain brand of soda in 16 OZ bottles is approximately normal .

Mean :

Standard deviation:

Let X be the random variable that represents the amount of soda in bottles.

Formula for z-score :

Z-score for 16 oz:

Using the standard normal z-distribution table , the probability that the soda bottles that contain more than the 16 OZ is given by :_

Hence, the percentage of the soda bottles that contain more than the 16 OZ advertised is 90.82% .

e^-kt = n/n0 = 0.79  

-kt = ln 0.79  

t = - ln 0.79/0.0001  

= 2357 years

step-by-step explanation: