Solve for x: (x+a)(x-b) = x^2 -1
how do i solve this ?

You must factor.

The factored form is equal to the assigned form.

Values a, b correspond to the factored 1, -1.

Value of x however remains unknown. But we can change that.

Given factored result,

We can set expression equal to 0 then find such x that when added with number a or b results with 0.

Hence x has 2 solutions.

Hope this helps.

Step-by-step explanation:

(x + a)(x - b) = x² - 1

(x + a)(x - b) = (x + 1)(x - 1)

By equality :

a = 1

b ÷ -1

b and c

step-by-step explanation: