Consider this system of equations. which equation represents the first equation written in slope-intercept form?
5x-2y=10
y=1/4x+1
a. y=5/2x-5
b. y=5/2x+10
c. y=-5/2x+10
d. y=-5x-5

A.   Y = 5/2x - 5.

Step-by-step explanation:

5X - 2Y = 10

-2Y = -5X + 10

Divide both sides by -2:

Y =  5/2x - 5.

A. 5/2 X - 5

Step-by-step explanation:

5x - 2y =10

To write the equation in a slope intercept we have to make y subject of the formular

5x - 2y = 10

we will take 2y to the right-handside and 10 to the left-handside

5x-10 = 2y

2y = 5x - 10

we divide bothside by 2

2y/2 = 5x/2 - 10/2

y = 5/2 X - 10