Adult entrance fees to amusement parks in the united states are normally distributed with a population standard deviation of 2.5 dollars and an unknown population mean. a random sample of 22 entrance fees at different amusement parks is taken and results in a sample mean of 61 dollars. find the margin of error for a 99% confidence interval for the population mean.

 1.509

Step-by-step explanation:

The formula of Margin of Error for (n<30):-

Given : Sample size : n= 22

Level of confidence = 0.99

Significance level :

Using the t-distribution table ,

Critical value :

Standard deviation:

Then, we have

Hence, the margin of error for a 99% confidence interval for the population mean =1.509

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step-by-step explanation:

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560

step-by-step explanation:

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