What are the vertical asymptotes of the function f(x) = the quantity of 4x plus 8, all over x squared plus 3x minus 4?
x = −1 and x = −2
x = −1 and x = 2
x = −1 and x = −4
x = 1 and x = −4

answer: 4x+8/x^2+3x-4 

vertical asymptotes are vertical lines which correspond to the zeroes of the denominator of a  rational function.

the vertical asymptotes (which tell me where the graph can  not  go) will be at the values 

4x+8/x^2+3x-4

if u solve the denominator x should not eqaul to 0

so x^2+3x-4=0 x=1,x=-4

step-by-step explanation:

yes. we do proportions in probabilities.

start with a line segment pq that we will copy. mark a point r that will be one endpoint of the new line segment. set the compasses' point on the point p of the line segment to be copied. adjust the compasses' width to the point q. the compasses' width is now equal to the length of the line segment pq.

step-by-step explanation: