Write an equation in slope-intercept form for the line passing through the pair of points.
(–1, 2), (4, –3)
a. y = 0x + 1
b. y = –x – 1
c. y = 0x – 1
d. y = –x + 1

Find the slope m.

m = (-3 -2)/(4 - (-1))

m = -5/(4 + 1)

m = -5/5

m = -1

Plug the slope and one of the points into the point-slope formula.

y - y_1 = m(x - x_1)

y - 2 = -1(x -(-1))

y - 2 = -1(x + 1)

The goal is to isolate y.

y - 2 = -x - 1

y = -x - 1 + 2

y = -x + 1

The answer is choice d.

Do you understand what I did here?

Step-by-step explanation:

The equation for a straight line is

y = mx + b

where m is the slope of the line and b is the y-intercept.

The line passes through the points (-1, 2) and (4, -3)

(a) Calculate the slope of the line

(b) Find the y-intercept

Insert the coordinates of one of the points into the equation

(c) Write the equation

The y-intercept is at x = 1.

The diagram shows the graph of the line passing through the two points with slope = -1.

answer: 7. if the functions had a negative leading coefficient and is of even degree, which statement about the graph is true?

step-by-step explanation: