Simultaneous equations:
find two numbers whose difference is 5 and whose sum is 11.

8 and 3

Step-by-step explanation:

Let x and y be the 2 numbers with x > y, then

x - y = 5 → (1)

x + y = 11 → (2)

Add the 2 equations together term by term to eliminate y

2x = 16 ( divide both sides by 2 )

x = 8

Substitute x = 8 into (2)

8 + y = 11 ( subtract 8 from both sides )

y = 3

The 2 numbers are 8 and 3

x=8 ; y=3

Step-by-step explanation:

suppose,

one of the number is x

other one is y ; x>y

according to the question,

x-y =5(1)

x+y=11(2)

(2)+(1)=>

x+y+x-y=11+5

2x=16

x=8            [divided by 2 on both side]

then,

(2)-(1)=>

x+y-x+y=11-5

2y=6

y=3              [divided by 2 on both side]

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!