Find the polar form of 1+ i / 1- i

hmmm let's start off by using the conjugate of the denominator to rationalize the denominator.

so the equation is really "i" in disguise, now, our coordinates are 0 and 1 for that complex point, we can't quite use tan⁻¹ to get the angle, since denominator is 0, meaning the point is lying on one of the axis, well, the rectangular (0,1) is right up above on the y-axis, namely at π/2.

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

step-by-step explanation:

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