If the area (in square units) of the region under the curve of the function f(x)=5 , on the interval from x=a to x=8 is 20 square units, what is the value of a?
answers: 4, 5, 6, 7, or 8?

8.

Step-by-step explanation:

In the question it says x=a then says x=8 if you do the common process of elimination you can concluded the a=8.

a = 4

Step-by-step explanation:

The function y = f(x) = 5 is simply a horizontal straight line

the interval x=a and x= 8 represent vertical straight lines that intersect x = a and x = 8.

Hence the area above the x-axis that is bound by f(x) on the top and x=a & x=8 on the sides is simply a rectangle with height = 5 and length = ( 8 - a ), and its area is given by

area = height x length = 5 (8-a)

we are given that the area = 20,

hence

area = 20 = 5(8-a)

(8-a) = 20/5

8-a = 4

-a = 4 - 8

-a = -4

a = 4

rectangle: 9 1/8 x 4 1/9 = 37 37/72in

parallelogram: b times h= 10.3 x 6.2 = 63.86

trapezoid: a+b/2 times h= 42.5

volume of prism: l times w times h= 36

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it