Amanufacturer of rechargeable laptop batteries markets its batteries as having, on
average, 500 charges. a consumer group decides to test this claim by assessing the
number of times 30 of their laptop batteries can be recharged and finds the average is 497, with a standard deviation of 10.the resulting p-value is .; thus, the null hypothesis is not rejected. the consumer group concludes that the manufacturer.

Let be the population mean.

By considering the given information , we have

, since the alternative hypothesis is two tailed , so the test is two tail test.

Given : Sample size : n=30

Sample mean :

Then, Standard deviation :

The p-value = 0.1111, the null hypothesis is not rejected.

Thus , we conclude that we have evidence to accept the company's claim that the batteries have on  average 500 charges.

78.59 is the mean

step-by-step explanation:

answer: a.

step-by-step explanation: the answer is a. because, you need to converge the fractions to find a solution.