Consider the following function. f(x) = x3/5, a = 1, n = 3, 0.7 ≤ x ≤ 1.3 (a) approximate f by a taylor polynomial with degree n at the number a. t3(x) = 3 5 (x−1)− 3 25 (x−1)2+ 7(x−1)3 125 +1 (b) use taylor's inequality to estimate the accuracy of the approximation f(x) ≈ tn(x) when x lies in the given interval. (round your answer to eight decimal places.) |r3(x)| ≤

4 adults and 12 babies

step-by-step explanation:

4 x 7 = 28

12 x 15 = 180

180 + 28 =208

4 x 3 = 12

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!

x = 3 ± √(5+y)