Arocket was launched into the air from a podium 6 feet off the ground. the rocket path is represented by the equation h(t)=-16t^2+120t+6, where h(t) represents the height, in feet, and t is the time, in seconds. find the average rate of change from the initial launch to the maximum height.

60

Step-by-step explanation:

The given function is:

The average rate of change of h(t) from t=a to t=b is given by:

We can rewrite this function as:

The maximum height of the rocket is 231 and it occurs at t=3.75

The initial launch occurs at: t=0

and

The average rate of change from the initial launch to the maximum height is

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.