What is the radius of a circle whose equation is x2+y2−10x+6y+18=0?

The radius is 4 units

Step-by-step explanation:

We can find the radius of a circle through the following procedure:

Complete the square for x and y  

Put in the format for a circle. (x-h)² + (y-k)² = r², center at (h,k) with radius = r

x2+y2−10x+6y+18=0

Now subtract 18 from both sides.

x^2+y^2−10x+6y+18-18=0-18

x^2 - 10x + y^2 + 6y = -18

(x-5)^2 - 25 + (y+3)^2 - 9 = -18

(x-5)^2 + (y+3)^2 = -18+9+25

(x-5)^2 + (y+3)^2 = 16

So,

r^2 = 16

Take square root at both sides:

√r^2 = √16

r = 4

Thus the radius is 4 units

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts