Atest has multiple choice questions with 5 choices for each answer, only one answer is correct for each question. suppose a student guesses the answer to each question. assuming the guesses are independent, find the probability that the student will not guess correctly on any one question.

The probability that the student will not guess correctly on any one question is 4/5

Step-by-step explanation:

The question posed is an application of the binomial probability distribution.

We have been informed that the test has multiple choice questions with 5 choices for each answer that only one answer is correct for each question.

If the student guesses the answer to each question, then the probability that the student will guess correctly on any one question is 1/5.

Therefore, the probability that the student will not guess correctly on any one question is;

1 - 1/5 = 4/5

the camry sales+accord sale=828,000. to make it so the two numbers are 18 thousand apart and still equal 828,000, you first need to find out what half of 828,000 is. 828,000/2=414,000. for the two numbers to equal 828,000, you have to add the same amount as you subtract from the middle. in this case, the number is 9,000 because it's half of 18,000. to equal 828,000, you have to add 9,000 to 414,000 for the camry and subtract 9,000 from 414,000 for the accord. 414,000+9,000=423,000.

414,000-9,000=405,000.

423,000+405,000=828,000.

423,000-405,000=18,

hope it

351°f

step-by-step explanation: