Let us assume that we are allowed to print so called college money used for shopping only within campus. the money is composed a unique serial numbers like m20130bc. it always starts with m, follows with five digital numbers chosen from 0 to 9, and then two letters chosen from a to z. a. what is the total number of such series numbers? b. what is the probability of getting the serial number mmm? c. what is the probability of getting a serial number whose last two letters to be aa?

a. 67600000

b. 0.0001396

c. 0.001479

Step-by-step explanation:

a. Since it is a permutation with repetition the formula is:

Where is the number of optionss, here you will use and , one for the numbers and the other for the letters. The exponent corresponds to how many times you have to choose a number (5 times) or a letter (two times because the first letter is always the same), then:

b. The probability of getting that exactly serial number is 1 divided by the total of possibilities:

C. The probability is the number of serials ending with AA divided by the total. The serial ending with AA can have any numbers then   and

step-by-step explanation:

no, her answer is not correct.   we square the lengths of all sides and then determine whether the pythagorean theorem holds here:

9² + 15² = 306.   this is not equal to the square of the longest side ( that square being 395.   answer c is correct.

given the equation is 8+9z=-6, the first step would be to subtract the 8 from both sides:

8+9z-8=-6-8

since 8 minus 8 = 0, this would cancel out the 8. and since -6 minus 8 equals -14, the equation would look like this

9z = -14