Find the critical points of dy/dx=15-2y-y^2 and determine if they are stable, unstable or semi-stable.

3...stable critical value, -5 unstable critical vale

Step-by-step explanation:

A critical value of the given differential is a value such that the left hand side of the equation is equal to zero, i.e, y such that

By the last equation the critical values of the given differential equation are y=-5, 3.

Now, since

It holdst that

and

hence 3 is a stable critical value.

Also note that

and

hence -5 is an unstable critical value.

4/6 = 2/3

so it should take 3/3 hours per man. so 9 hours is the answer 3*3 =9

step-by-step explanation: