What is the value of x in the equation 4x+8y=40, when y=0.8 ?

The value of x is 8.4

Step-by-step explanation:

The given equation is:

4x+8y=40

where y = 0.8 = 8/10

Put the value of y in the given equation:

4x+8(0.8)=40

4x+6.4 = 40

Combine the like terms:

We get,

4x=40-6.4

4x= 33.6

Now divide both sides by 4

4x/4 = 33.6/4

x=8.4

Thus the value of x is 8.4

Step-by-step explanation:

You have the following equation:

 In order to find the value of the variable "x" when , you need to substitute this value of "y" into the given equation and then you must solve for  "x".

Applying this procedure, you get the following value of "x":

the infinity sign

step-by-step explanation:

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3