In a library, bookcases a, b,c and d are lined up in order. bookcase a is 1.38 meters from bookcase b and 6.8 meters from bookcase c. bookcase d is 0.925 meters farther from bookcase c than the distance between bookcases b and c. how far apart are bookcases c and d? (show your work).

Bookcases C and D are 6.345 meters apart

Explanation:

The given scenario can be modeled using the attached diagram

Assume that the distance between cases B and C is x meters

We are given that:

Distance between cases A and B is 1.38 m

Distance between cases A and C is 6.8 m

We know that:

Distance between A & C = Distance between A & B + Distance between  B & C

This means that:

6.8 = 1.38 + x

x = 6.8 - 1.38 = 5.42 m

Now, we are given that bookcase D is 0.925 meters farther from bookcase C than the distance between bookcases B and C

This means that:

Distance between cases C & D = Distance between cases B & C + 0.925

Distance between cases C & D = x + 0.925

Distance between cases C & D = 5.42 + 0.925

Distance between cases C & D = 6.345 meters

Hope this helps :)

part 1 answer = 8

part 2 answer = 72

step-by-step explanation:

part 1 explanation = add all of the numbers, then divide by how many numbers you have. so, 200/25 = 8.

part 2 explanation = not gonna lie, this is hard to explain, so just google how to do it.

y-y1=4(x-x1)

step-by-step explanation:

this is point-slope form since you only have 4 as the slope it goes in place of m

hope this : )