Kx - 3y = 4
4x - 5y = 7
in the system of equations above, k is a constant
and y are variables. for what value of k will
che sistem of equations have no solution?

k=12/5=2.4

Step-by-step explanation:

1. Let's get rid of the variable y

Multiply the first equation by 5 and the second by 3

5kx-15y=20

12x-15y=60

Now subtract from equation(2)/equation(1) -> 12x-5kx=40

x(12-5k)=40 This equation is always solvable except if 12-5k=0, and this happens if k=12/5=2.4

domain is all the x values included in the

0 ≤ x ≤ 2

range is all the y values of the graph

-2 ≤ y ≤ 2

***keep in mind that there are different ways to show domain and range

hope this !

~just a girl in love with shawn mendes

  the correct choice is marked

step-by-step explanation:

the first two graphs show multiple turning points. the last graphs matches the description in every detail.