You roll a six-sided die. find the probability of each of the following scenarios. (a) rolling a 55 or a number greater than 33 (b) rolling a number less than 55 or an even number

 a)

b)

Step-by-step explanation:

When you roll a six-sided die , then the total number of outcomes = 6

The number greater than 3= 4, 5 ,6

The favorable outcomes of rolling a 5 or a number greater than 3 = 4, 5 ,6

Then , the probability that the rolling a 5 or a number greater than 3 is given by :-

The favorable outcomes for the rolling a number less than 5 or an even number =2, 4

Then the probability that the rolling a number less than 5 or an even number :-

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?