Consider the equation of the tractrix y = a sech−1(x/a) − a2 − x2 , a > 0. (a) find dy/dx. dy dx = − a2 x√x+a√−x+a+ x √a2−x2 (b) let l be the tangent line to the tractrix at the point p. when l intersects the y-axis at the point q, show that the distance between p and q is a.

at least two

step-by-step explanation:

the equation of the parallel line would be y = 2x + 9

step-by-step explanation:

to start we need to find the slope of the original line. we can do that by looking at the coefficient of x, which is 2

since the slope of the original line is 2 and parallel lines have the same slope, we know the new line will also have 2 slope. now we can use that along with the point given in point-slope form to get the find equation.

y - y1 = m(x - x1)

y - 5 = 2(x + 2)

y - 5 = 2x + 4

y = 2x + 9

1. 523.33 cubic inches

2. 113.04 cubic inches.

3. 17.41.

4. 16.49

i think this should be your answer

hope i

-lavira : )