Suppose there is sufficient evidence to reject upper h 0 : mu 1 equals mu 2 equals mu 3 using a one-way anova. the mean square error from the anova is determined to be 23.3. the sample means are x overbar 1 equals 3.8, x overbar 2 equals 10.4, and x overbar 3 equals 19.1, with n 1 equals n 2 equals n 3 equals 6. use tukey's test to determine which pairwise means are significantly different using a familywise error rate of alpha equals 0.01.

15 ! will give ! 1. simplify 100 squared. a 20 b 10 (pretty sure it's 10) c 50 d 25 2. simplify 27/12 squared a 13/6 b 2/3 c 3/2 (pretty sure it's 3/2) d 3 3. find the square root of 0.49 a 7 b 0.07 c 0.007 d 0.7 (almost completely sure its 0.7) 4. simplify fully. 2 5 squared + 3 5 squared - 5 squared a 5 5 squared (pretty sure its this one) b 4 5 squared c 5 15 squared d 4 15 squared 5. simplify 2 squared * 800 squared a 20 b 40 c 80 d 400