Abuilding needs a ramp to make it handicap accessible. by law, the ramp must run 10 inches horizontally for every 1 inch of rise. if the surface of the ramp is 57 inches long how far above the ground is the inclined end of the ramp? round to the nearest tenth of an inch.

The inclined end of the ramp is 5.7 in above the ground

Step-by-step explanation:

step 1

we know that

The ramp must run 10 inches horizontally for every 1 inch of rise

Applying the Pythagoras Theorem, find the hypotenuse

step 2

Using proportion find out the height of the ramp

Let

x ----> the height of the ramp

Inclined ramp will be 5.7 inches above the ground.

Step-by-step explanation:

A building needs a ramp to make it handicap accessible.

Law says, "the ram must run 10 inches horizontally for every 1 inch rise".

In the figure attached, ramp is given with a horizontal length 10 inches and vertical rise 1 inch.

Length of hypotenuse of the right triangle = [By Pythagoras theorem]

                                                                      =

                                                                      =

Now a second ramp is given which is similar to the previous one with the hypotenuse 57 inches and we have to calculate the vertical length.

By the property of similar triangles - "All corresponding sides will be in the same ratio"

x =

  =

  = 5.67 inches

  ≈ 5.7 inches

5.762159

step-by-step explanation:

it would be 9 because when it is the nine is over five so that would mean it rounds up to 90 or 9

ending amount = beginning amount / (2^n)

where "n" = number of half-lives (or elapsed time / half-life)

ending amount = 50 mg / (2 ^10 / 5.3)

ending amount = 50 mg / (2 ^ 1.8867924528)

ending amount = 50 m / 3.6981210597

ending amount = 13.5203794557 mg

or about 13.5 mg remain

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