Adog kennel owner has 147ft. of fencing to enclose a rectangular dog run. she wants it to be 6times as long as it is wide. find the dimensions

length = 63 ft; width = 10.5 ft

Step-by-step explanation:

Let the width be x.

The length is 6 times the width, so the length is 6x.

The perimeter is the sum of 2 lengths and 2 widths.

6x + 6x + x + x

The perimeter equals 147 ft.

6x + 6x + x + x = 147

14x = 147

x = 10.5

The width is 10.5 ft.

The length is 6x, so the length is 6 * 10.5 ft = 63 ft

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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